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@REPLY: <878r9nxsav.fsf@bsb.me.uk> e8279370
@REPLYADDR hongy...@gmail.com
<hongyi.zhao@gmail.com>
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@PID: G2/1.0
@TID: FIDOGATE-5.12-ge4e8b94
On Sunday, September 3, 2023 at 10:09:03 PM UTC+8, Ben Bacarisse wrote:
> "
hongy...@gmail.com" <
hongy...@gmail.com> writes:
>
> > I want to split a hex string into bytes and compute their
xor, as shown below:
> >
> > werner@X10DAi:~$ data=$( sed `s/\\(..\\)/\\1 /g` <<<
23230DFE4C5336413245313636504135303333333401000A130A1814300A01010101 | sed -e `s/[ ]*$//` )
> > werner@X10DAi:~$ IFS=` ` read -ra ADDR <<< "$data"; xor=0; for
i in "${ADDR[@]}"; do xor=$((xor ^ 0x$i)); done; printf `%x
` $xor
> > ea
> >
> > I wonder if there is a more concise and simple method for this
> > purpose.
> You could construct the expression directly. With only two bytes for
> clarity:
>
> printf `%x
` $(($(sed `s/\\(..\\)/0x\\1^/g` <<<2324)0))
>
> The 0 at the end is needed because the sed command adds a trailing ^
> operator.
Good solution. I have confirmed all the approaches suggested above as follows:
werner@X10DAi:~$ gawk `{ x = 0; for (i=1; i<=NF; i++) x =
xor(x,strtonum("0x" $i)); printf("%x
", x) }` FPAT=.. <<<
23230DFE4C5336413245313636504135303333333401000A130A1814300A01010101
ea
werner@X10DAi:~$ gawk `{ x = 0; for (i=1; i<=NF; i++) x =
xor(x,strtonum("0x" $i)); printf "%x
", x }` FPAT=.. <<<
23230DFE4C5336413245313636504135303333333401000A130A1814300A01010101
ea
werner@X10DAi:~$ printf `%x
` $(($(sed `s/\\(..\\)/0x\\1^/g` <<<
23230DFE4C5336413245313636504135303333333401000A130A1814300A01010101)0))
ea
> --
> Ben.
Regards,
Zhao
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